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The LED and potentiometer are connected where they should be receiving somewhere near 11V after you subtract the voltage drop from the diodes and how it's around a 4.7V output (the multimeter is monitoring the voltage of the second capacitor, not the total voltage of the circuit, when I measure the total voltage, it's just showing up as 4.7V). I've tried removing the LED and potentiometer and the capacitor just slowly discharges.
Do you know why the voltage wouldn't drop until I used a digitalRead(C9)? Shouldn't just calling the digitalWrite(C9,0) cut the signal?
user52526
It looks to me like you're maybe drawing too much power out of it. Where is the LED connected?
What happens if you just totally disconnect the potentiometer and the LED and then look at the voltage that you get?