Calling super() from sub-sub-class leads to infinite loop

@OP, this probably won't help you directly.

I have done some reading about super lately. Here's a summary:

• functions created with funcName() syntax (as in class { }) have a hidden attribute pointing to their "HomeObject" - C.prototype and B.prototype in the example here.
  
  • also true in an object-literal like { foo() { } }, as a pedantic side note
    
• super is (should be) Object.prototypeOf(HomeObject)
  
• in constructor, super() is shorthand for super.constructor()
  
  

It looks like the call to super at line 7 may be resolving super as Object.prototypeOf(this) instead.

https://2ality.com/2011/11/super-referen­ces.html

HTH someone