user115787

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• Calling super() from sub-sub-class leads to infinite loop

  in JavaScript • 3 years, 9 months

  

  @OP, this probably won't help you directly.

  I have done some reading about super lately. Here's a summary:

  • functions created with funcName() syntax (as in class { }) have a hidden attribute pointing to their "HomeObject" - C.prototype and B.prototype in the example here.
    
    • also true in an object-literal like { foo() { } }, as a pedantic side note
      
  • super is (should be) Object.prototypeOf(HomeObject)
    
  • in constructor, super() is shorthand for super.constructor()
    
    

  It looks like the call to super at line 7 may be resolving super as Object.prototypeOf(this) instead.

  https://2ality.com/2011/11/super-referen­ces.html

  HTH someone